Laman

Like

BAGI ANDA MERASA INI BERMANFAAT SILAHKAN LIKE PAGE ON FACEBOOK DIBAWAH INI!!!


Like Page halaman http://iswahyuniiswahyuni.blogspot.com/ di Facebook!!

Minggu, 08 Juni 2014

Kuis Sistem Pendukung Keputusan (SPK)

Soal Quiz Online Klik Disini

Penyelesaian:

No
Nama
C1
C2
C3
C4
1
Joko
3
3
3
2
2
Widodo
3
3
2
2
3
Simamora
4
4
1
1
4
Susilawati
1
4
2
1
5
Dian
2
3
4
2
6
Roma
2
2
4
2
7
Hendro
3
2
3
2

Bobot W=[ 3, 4, 5, 4 ]


Untuk C1
X1 = √32+32+42+12+22+22+32
     = √9+9+16+1+4+4+9
     = √52
     = 7.2111
R11 = 3 / 7.2111
       = 0.4160
R21 = 3 / 7.2111
       = 0.4160
R31 = 4 / 7.2111
       = 0.5547
R41 = 1 / 7.2111
       = 0.1386
R51 = 2 / 7.2111
       = 0.2773
R61 = 2 / 7.2111
       = 0.2773
R71 = 3 / 7.2111
       = 0.4160


Untuk C2
X2 = √32+32+42+42+32+22+22
        = √9+9+16+16+9+4+4
     = √67
     = 8.1853

R12 = 3 / 8.1853
       = 0.3665
R22 = 3 / 8.1853
       = 0.3665
R32 = 4 / 8.1853
       = 0.4886
R42 = 4 / 8.1853
       = 0.4886
R52 = 3 / 8.1853
       = 0.3665
R62 = 2 / 8.1853
       = 0.2443
R72 = 2 / 8.1853
       = 0.2443
Untuk C3
X3 = √32+22+12+22+42+42+32
        = √9+4+1+4+16+16+9
     = √59
     = 7.6811

R13 = 3 / 7.6811
       = 0.3905
R23 = 2 / 7.6811
       = 0.2603
R33 = 1 / 7.6811
       = 0.1301
R43 = 2 / 7.6811
       = 0.2603
R53 = 4 / 7.6811
       = 0.5207
R63 = 4 / 7.6811
       = 0.5207
R73 = 3 / 7.6811
       = 0.3905
Untuk C4
X4 = √22+22+12+12+22+22+22
        = √4+4+1+1+4+4+4
     = √22
     = 4.6904
R14 = 2 / 4.6904
       = 0.4264
R24 = 2 / 4.6904
       = 0.4264
R34 = 1 / 4.6904
       = 0.2132
R44 = 1 / 4.6904
       = 0.2132
R54 = 2 / 4.6904
       = 0.4264
R64 = 2 / 4.6904
       = 0.4264
R74 = 2 / 4.6904
       = 0.4264
Matriks R ternormalisasi

                        0.4160                        0.3665                        0.3905                        0.4264

0.4160                        0.3665                        0.2603                        0.4264

0.5547                        0.4886                        0.1301                        0.2132

0.1386                        0.4886                        0.2603                        0.2132

0.2773                        0.3665                        0.5207                        0.4264

0.2773                        0.2443                        0.5207                        0.4264

0.4160                        0.2443                        0.3905                        0.4264
Yij = wiRij  dimana Bobot W=[ 3, 4, 5, 4 ]

Y11 = 3(0.4160) = 1.248        
Y21 = 3(0.4160) = 1.248        
Y31 = 3(0.5547) = 1.6641        
Y41 = 3(0.1386) = 0.4158         
Y51 = 3(0.2773) = 0.8319        
Y61 = 3(0.2773) = 0.8319        
Y71 =3(0.4160)  = 1.248        

Y12=4(0.3665) = 1.466      
Y22=4(0.3665) =1.466       
Y32=4(0.4886) = 1.9544     
Y42=4(0.4886) = 1.9544      
Y52=4(0.3665) =1.466       
Y62=4(0.2443) =0.9772       
Y72=4(0.2443) =0.9772    

Y13=5(0.3905) =1.9525   
Y23=5(0.2603) =1.3015       
Y33=5(0.1301) =0.6505       
Y43=5(0.2603) = 1.3015     
Y53=5(0.5207) = 2.6035      
Y63=5(0.5207) =2.6035      
Y73=5(0.3905) =1.9525       

Y14=4(0.4264) = 1.7056
Y24=4(0.4264) = 1.7056
Y34=4(0.2132) = 0.8528
Y44=4(0.2132) = 0.8528
Y54=4(0.4264) = 1.7056
Y64=4(0.4264) = 1.7056
Y74=4(0.4264) = 1.7056

Matriks Y ternormalisasi
                        
                        1.248              1.466              1.9525                        1.7056
1.248              1.466              1.3015                        1.7056
1.6641            1.9544            0.6505                        0.8528
0.4158            1.9544            1.3015                        0.8528
0.8319            1.466              2.6035                        1.7056
0.8319            0.9772            2.6035                        1.7056
1.248              0.9772            1.9525                        1.7056

Solusi Ideal Positif (A+)
Y1 +  = MAX {1.248  ; 1.248  ; 1.6641; 0.4158; 0.8319; 0.8319; 1.248  }   = 1.6641
Y2 +  = MAX {1.466  ; 1.466  ; 1.9544; 1.9544; 1.466  ; 0.9772; 0.9772}   = 1.9544
Y3 +  = MIN  {1.9525; 1.3015; 0.6505; 1.3015; 2.6035; 2.6035; 1.9525}  = 0.6505
Y4 +  = MAX {1.7056; 1.7056; 0.8528; 0.8528; 1.7056; 1.7056; 1.7056}  = 1.7056
A+ = (1.6641 ; 1.9544 ; 0.6505; 1.7056)

Solusi Ideal Positif (A- )
Y1 -  = MIN {1.248  ; 1.248  ; 1.6641; 0.4158; 0.8319; 0.8319; 1.248  }    = 0.4158
Y2 -  = MIN {1.466  ; 1.466  ; 1.9544; 1.9544; 1.466  ; 0.9772; 0.9772}    = 0.9772
Y3 -  = MAX  {1.9525; 1.3015; 0.6505; 1.3015; 2.6035; 2.6035; 1.9525}  = 2.6035
Y4 -  = MIN {1.7056; 1.7056; 0.8528; 0.8528; 1.7056; 1.7056; 1.7056}   = 0.8528
A- = (0.4158 ; 0.9772 ; 2.6035 ; 0.8528)

Jarak Alternatif Terbobot dengan Solusi Ideal Positif
D1+ = √(1.248-1.6641)2 + (1.466-1.9544)2 + (1.9525-0.6505)2 + (1.7056-1.7056)2
       = √2.1068
       = 1.4514
D2+ = √(1.248-1.6641)2 + (1.466-1.9544)2 + (1.3015-0.6505)2 + (1.7056-1.7056)2
       = √0.8354
       = 0.9140
D3+ = √(1.6641-1.6641)2 + (1.9544-1.9544)2 + (0.6505-0.6505)2 + (0.8528-1.7056)2
       = √0.7272
       = 0.8527
D4+ = √(0.4158-1.6641)2 + (1.9544-1.9544)2 + (1.3015-0.6505)2 + (0.8528-1.7056)2
       = √2.7093
       = 1.6459
D5+ = √(0.8319-1.6641)2 + (1.466-1.9544)2 + (2.6035-0.6505)2 + (1.7056-1.7056)2
       = √4.7453
       = 2.1783
D6+ = √(0.8319-1.6641)2 + (0.9772-1.9544)2 + (2.6035-0.6505)2 + (1.7056-1.7056)2
       = √5.4616
       =2.3370
D7+ = √(1.248-1.6641)2 + (0.9772-1.9544)2 + (1.9525-0.6505)2 + (1.7056-1.7056)2)
       = √2.8232
       = 1.6802


Jarak Alternatif Terbobot dengan Solusi Ideal Negatif
D1- = √(1.248-0.4158)2 + (1.466-0.9772)2 + (1.9525-2.6035)2 + (1.7056-0.8528)2)
      = √2.0825
      = 1.4430
D2- = √(1.248-0.4158)2 + (1.466-0.9772)2 + (1.3015-2.6035)2 + (1.7056-0.8528)2)
      = √3.3539
      = 1.8313
D3- = √(1.6641-0.4158)2 + (1.9544-0.9772)2 + (0.6505-2.6035)2 + (0.8528-0.8528)2)
       = √6.3273
       = 2.5154
D4- = √(0.4158-0.4158)2 + (1.9544-0.9772)2 + (1.3015-2.6035)2 + (0.8528-0.8528)2
       = √2.6501
       = 1.6279
D5- = √(0.8319-0.4158)2 + (1.466-0.9772)2 + (2.6035-2.6035)2 + (1.7056-0.8528)2)
      = √1.1393
      = 1.0673
D6- = √(0.8319-0.4158)2 + (0.9772-0.9772)2 + (2.6035-2.6035)2 + (1.7056-0.8528)2
      = √0.9004
      =0.9488
D7- = √(1.248-0.4158)2 + (0.9772-0.9772)2 + (1.9525-2.6035)2 + (1.7056-0.8528)2
       = √1.8436
       = 1.3577
Nilai Preferensi untuk Setiap Alternatif (Vi)
V1 = 1.4430 / (1.4430 + 1.4514) = 0.4985  
V2 = 1.8313 / (1.8313 + 0.9140) = 0.6670 
V3 = 2.5154/ (2.5154 + 0.8527) = 0.7468
V4 = 1.6279/ (1.6279 + 1.6459) = 0.4972
V5 = 1.0673 / (1.0673 + 2.1783) = 0.3295
V6 = 0.9488 / (0.9488 + 2.3370) = 0.2887
V7 = 1.3577/ (1.3577 + 1.6802) = 0.4469

Jadi, 5 mahasiswa yang berhak untuk mendapatkan beasiswa adalah Joko, Widodo, Simamora, Susilawati, dan Hendro.

Nama : Iswahyuni
NPM   : 1111706
Kelas : TI-P1101

Diposting oleh di
Label:

Tidak ada komentar:

Posting Komentar

Langganan: Posting Komentar (Atom)